Integrand size = 37, antiderivative size = 572 \[ \int \frac {(g \cos (e+f x))^{5/2}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\frac {a g^{5/2} \arctan \left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} b^2 \sqrt {d} f}-\frac {a g^{5/2} \arctan \left (1+\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} b^2 \sqrt {d} f}-\frac {a g^{5/2} \log \left (\sqrt {g}+\sqrt {g} \cot (e+f x)-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}\right )}{2 \sqrt {2} b^2 \sqrt {d} f}+\frac {a g^{5/2} \log \left (\sqrt {g}+\sqrt {g} \cot (e+f x)+\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}\right )}{2 \sqrt {2} b^2 \sqrt {d} f}+\frac {2 \sqrt {2} \sqrt {-a+b} \sqrt {a+b} g^{5/2} \operatorname {EllipticPi}\left (-\frac {\sqrt {-a+b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {1+\sin (e+f x)}}\right ),-1\right ) \sqrt {\sin (e+f x)}}{b^2 f \sqrt {d \sin (e+f x)}}-\frac {2 \sqrt {2} \sqrt {-a+b} \sqrt {a+b} g^{5/2} \operatorname {EllipticPi}\left (\frac {\sqrt {-a+b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {1+\sin (e+f x)}}\right ),-1\right ) \sqrt {\sin (e+f x)}}{b^2 f \sqrt {d \sin (e+f x)}}-\frac {g^2 \sqrt {g \cos (e+f x)} E\left (\left .e-\frac {\pi }{4}+f x\right |2\right ) \sqrt {d \sin (e+f x)}}{b d f \sqrt {\sin (2 e+2 f x)}} \]
-1/2*a*g^(5/2)*arctan(-1+2^(1/2)*d^(1/2)*(g*cos(f*x+e))^(1/2)/g^(1/2)/(d*s in(f*x+e))^(1/2))/b^2/f*2^(1/2)/d^(1/2)-1/2*a*g^(5/2)*arctan(1+2^(1/2)*d^( 1/2)*(g*cos(f*x+e))^(1/2)/g^(1/2)/(d*sin(f*x+e))^(1/2))/b^2/f*2^(1/2)/d^(1 /2)-1/4*a*g^(5/2)*ln(g^(1/2)+cot(f*x+e)*g^(1/2)-2^(1/2)*d^(1/2)*(g*cos(f*x +e))^(1/2)/(d*sin(f*x+e))^(1/2))/b^2/f*2^(1/2)/d^(1/2)+1/4*a*g^(5/2)*ln(g^ (1/2)+cot(f*x+e)*g^(1/2)+2^(1/2)*d^(1/2)*(g*cos(f*x+e))^(1/2)/(d*sin(f*x+e ))^(1/2))/b^2/f*2^(1/2)/d^(1/2)+2*g^(5/2)*EllipticPi((g*cos(f*x+e))^(1/2)/ g^(1/2)/(1+sin(f*x+e))^(1/2),-(-a+b)^(1/2)/(a+b)^(1/2),I)*2^(1/2)*(-a+b)^( 1/2)*(a+b)^(1/2)*sin(f*x+e)^(1/2)/b^2/f/(d*sin(f*x+e))^(1/2)-2*g^(5/2)*Ell ipticPi((g*cos(f*x+e))^(1/2)/g^(1/2)/(1+sin(f*x+e))^(1/2),(-a+b)^(1/2)/(a+ b)^(1/2),I)*2^(1/2)*(-a+b)^(1/2)*(a+b)^(1/2)*sin(f*x+e)^(1/2)/b^2/f/(d*sin (f*x+e))^(1/2)+g^2*(sin(e+1/4*Pi+f*x)^2)^(1/2)/sin(e+1/4*Pi+f*x)*EllipticE (cos(e+1/4*Pi+f*x),2^(1/2))*(g*cos(f*x+e))^(1/2)*(d*sin(f*x+e))^(1/2)/b/d/ f/sin(2*f*x+2*e)^(1/2)
Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.
Time = 25.37 (sec) , antiderivative size = 1399, normalized size of antiderivative = 2.45 \[ \int \frac {(g \cos (e+f x))^{5/2}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx =\text {Too large to display} \]
((g*Cos[e + f*x])^(5/2)*Sqrt[Sin[e + f*x]]*((Sqrt[Tan[e + f*x]]*((3*Sqrt[2 ]*a^(3/2)*(-2*ArcTan[1 - (Sqrt[2]*(a^2 - b^2)^(1/4)*Sqrt[Tan[e + f*x]])/Sq rt[a]] + 2*ArcTan[1 + (Sqrt[2]*(a^2 - b^2)^(1/4)*Sqrt[Tan[e + f*x]])/Sqrt[ a]] - Log[-a + Sqrt[2]*Sqrt[a]*(a^2 - b^2)^(1/4)*Sqrt[Tan[e + f*x]] - Sqrt [a^2 - b^2]*Tan[e + f*x]] + Log[a + Sqrt[2]*Sqrt[a]*(a^2 - b^2)^(1/4)*Sqrt [Tan[e + f*x]] + Sqrt[a^2 - b^2]*Tan[e + f*x]]))/(a^2 - b^2)^(1/4) - 8*b*A ppellF1[3/4, 1/2, 1, 7/4, -Tan[e + f*x]^2, ((-a^2 + b^2)*Tan[e + f*x]^2)/a ^2]*Tan[e + f*x]^(3/2))*(b*Tan[e + f*x] + a*Sqrt[1 + Tan[e + f*x]^2]))/(12 *a^2*Cos[e + f*x]^(3/2)*Sqrt[Sin[e + f*x]]*(a + b*Sin[e + f*x])*(1 + Tan[e + f*x]^2)^(3/2)) + (Cos[2*(e + f*x)]*Sqrt[Tan[e + f*x]]*(b*Tan[e + f*x] + a*Sqrt[1 + Tan[e + f*x]^2])*(56*b*(-3*a^2 + b^2)*AppellF1[3/4, 1/2, 1, 7/ 4, -Tan[e + f*x]^2, (-1 + b^2/a^2)*Tan[e + f*x]^2]*Tan[e + f*x]^(3/2) + 24 *b*(-a^2 + b^2)*AppellF1[7/4, 1/2, 1, 11/4, -Tan[e + f*x]^2, (-1 + b^2/a^2 )*Tan[e + f*x]^2]*Tan[e + f*x]^(7/2) + 21*a^(3/2)*(4*Sqrt[2]*a^(3/2)*ArcTa n[1 - Sqrt[2]*Sqrt[Tan[e + f*x]]] - 4*Sqrt[2]*a^(3/2)*ArcTan[1 + Sqrt[2]*S qrt[Tan[e + f*x]]] - (4*Sqrt[2]*a^2*ArcTan[1 - (Sqrt[2]*(a^2 - b^2)^(1/4)* Sqrt[Tan[e + f*x]])/Sqrt[a]])/(a^2 - b^2)^(1/4) + (2*Sqrt[2]*b^2*ArcTan[1 - (Sqrt[2]*(a^2 - b^2)^(1/4)*Sqrt[Tan[e + f*x]])/Sqrt[a]])/(a^2 - b^2)^(1/ 4) + (4*Sqrt[2]*a^2*ArcTan[1 + (Sqrt[2]*(a^2 - b^2)^(1/4)*Sqrt[Tan[e + f*x ]])/Sqrt[a]])/(a^2 - b^2)^(1/4) - (2*Sqrt[2]*b^2*ArcTan[1 + (Sqrt[2]*(a...
Time = 2.30 (sec) , antiderivative size = 552, normalized size of antiderivative = 0.97, number of steps used = 23, number of rules used = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.595, Rules used = {3042, 3380, 3042, 3317, 3042, 3052, 3042, 3055, 826, 1476, 1082, 217, 1479, 25, 27, 1103, 3119, 3385, 3042, 3384, 993, 1542}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(g \cos (e+f x))^{5/2}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {(g \cos (e+f x))^{5/2}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx\) |
\(\Big \downarrow \) 3380 |
\(\displaystyle \frac {g^2 \int \frac {\sqrt {g \cos (e+f x)} (a-b \sin (e+f x))}{\sqrt {d \sin (e+f x)}}dx}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {g^2 \int \frac {\sqrt {g \cos (e+f x)} (a-b \sin (e+f x))}{\sqrt {d \sin (e+f x)}}dx}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 3317 |
\(\displaystyle \frac {g^2 \left (a \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}dx-\frac {b \int \sqrt {g \cos (e+f x)} \sqrt {d \sin (e+f x)}dx}{d}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {g^2 \left (a \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}dx-\frac {b \int \sqrt {g \cos (e+f x)} \sqrt {d \sin (e+f x)}dx}{d}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 3052 |
\(\displaystyle \frac {g^2 \left (a \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}dx-\frac {b \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {g^2 \left (a \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}dx-\frac {b \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 3055 |
\(\displaystyle \frac {g^2 \left (-\frac {2 a d g \int \frac {g \cot (e+f x)}{d \left (\cot ^2(e+f x) g^2+g^2\right )}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{f}-\frac {b \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 826 |
\(\displaystyle \frac {g^2 \left (-\frac {2 a d g \left (\frac {\int \frac {\cot (e+f x) g+g}{\cot ^2(e+f x) g^2+g^2}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 d}-\frac {\int \frac {g-g \cot (e+f x)}{\cot ^2(e+f x) g^2+g^2}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 d}\right )}{f}-\frac {b \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 1476 |
\(\displaystyle \frac {g^2 \left (-\frac {2 a d g \left (\frac {\frac {\int \frac {1}{\frac {\cot (e+f x) g}{d}+\frac {g}{d}-\frac {\sqrt {2} \sqrt {g \cos (e+f x)} \sqrt {g}}{\sqrt {d} \sqrt {d \sin (e+f x)}}}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 d}+\frac {\int \frac {1}{\frac {\cot (e+f x) g}{d}+\frac {g}{d}+\frac {\sqrt {2} \sqrt {g \cos (e+f x)} \sqrt {g}}{\sqrt {d} \sqrt {d \sin (e+f x)}}}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 d}}{2 d}-\frac {\int \frac {g-g \cot (e+f x)}{\cot ^2(e+f x) g^2+g^2}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 d}\right )}{f}-\frac {b \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 1082 |
\(\displaystyle \frac {g^2 \left (-\frac {2 a d g \left (\frac {\frac {\int \frac {1}{-\frac {g \cot (e+f x)}{d}-1}d\left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\int \frac {1}{-\frac {g \cot (e+f x)}{d}-1}d\left (\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}+1\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}-\frac {\int \frac {g-g \cot (e+f x)}{\cot ^2(e+f x) g^2+g^2}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 d}\right )}{f}-\frac {b \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 217 |
\(\displaystyle \frac {g^2 \left (-\frac {2 a d g \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}+1\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}-\frac {\int \frac {g-g \cot (e+f x)}{\cot ^2(e+f x) g^2+g^2}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 d}\right )}{f}-\frac {b \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 1479 |
\(\displaystyle \frac {g^2 \left (-\frac {2 a d g \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}+1\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}-\frac {-\frac {\int -\frac {\sqrt {2} \sqrt {g}-\frac {2 \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{\sqrt {d} \left (\frac {\cot (e+f x) g}{d}+\frac {g}{d}-\frac {\sqrt {2} \sqrt {g \cos (e+f x)} \sqrt {g}}{\sqrt {d} \sqrt {d \sin (e+f x)}}\right )}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 \sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\int -\frac {\sqrt {2} \left (\sqrt {g}+\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}\right )}{\sqrt {d} \left (\frac {\cot (e+f x) g}{d}+\frac {g}{d}+\frac {\sqrt {2} \sqrt {g \cos (e+f x)} \sqrt {g}}{\sqrt {d} \sqrt {d \sin (e+f x)}}\right )}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 \sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}\right )}{f}-\frac {b \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {g^2 \left (-\frac {2 a d g \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}+1\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}-\frac {\frac {\int \frac {\sqrt {2} \sqrt {g}-\frac {2 \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{\sqrt {d} \left (\frac {\cot (e+f x) g}{d}+\frac {g}{d}-\frac {\sqrt {2} \sqrt {g \cos (e+f x)} \sqrt {g}}{\sqrt {d} \sqrt {d \sin (e+f x)}}\right )}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 \sqrt {2} \sqrt {d} \sqrt {g}}+\frac {\int \frac {\sqrt {2} \left (\sqrt {g}+\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}\right )}{\sqrt {d} \left (\frac {\cot (e+f x) g}{d}+\frac {g}{d}+\frac {\sqrt {2} \sqrt {g \cos (e+f x)} \sqrt {g}}{\sqrt {d} \sqrt {d \sin (e+f x)}}\right )}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 \sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}\right )}{f}-\frac {b \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {g^2 \left (-\frac {2 a d g \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}+1\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}-\frac {\frac {\int \frac {\sqrt {2} \sqrt {g}-\frac {2 \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{\frac {\cot (e+f x) g}{d}+\frac {g}{d}-\frac {\sqrt {2} \sqrt {g \cos (e+f x)} \sqrt {g}}{\sqrt {d} \sqrt {d \sin (e+f x)}}}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 \sqrt {2} d \sqrt {g}}+\frac {\int \frac {\sqrt {g}+\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{\frac {\cot (e+f x) g}{d}+\frac {g}{d}+\frac {\sqrt {2} \sqrt {g \cos (e+f x)} \sqrt {g}}{\sqrt {d} \sqrt {d \sin (e+f x)}}}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}}{2 d \sqrt {g}}}{2 d}\right )}{f}-\frac {b \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 1103 |
\(\displaystyle \frac {g^2 \left (-\frac {b \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d \sqrt {\sin (2 e+2 f x)}}-\frac {2 a d g \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}+1\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}-\frac {\frac {\log \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\log \left (-\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}\right )}{f}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 3119 |
\(\displaystyle \frac {g^2 \left (-\frac {2 a d g \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}+1\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}-\frac {\frac {\log \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\log \left (-\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}\right )}{f}-\frac {b E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d f \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2}\) |
\(\Big \downarrow \) 3385 |
\(\displaystyle \frac {g^2 \left (-\frac {2 a d g \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}+1\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}-\frac {\frac {\log \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\log \left (-\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}\right )}{f}-\frac {b E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d f \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \sqrt {\sin (e+f x)} \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {\sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2 \sqrt {d \sin (e+f x)}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {g^2 \left (-\frac {2 a d g \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}+1\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}-\frac {\frac {\log \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\log \left (-\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}\right )}{f}-\frac {b E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d f \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}-\frac {g^2 \left (a^2-b^2\right ) \sqrt {\sin (e+f x)} \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {\sin (e+f x)} (a+b \sin (e+f x))}dx}{b^2 \sqrt {d \sin (e+f x)}}\) |
\(\Big \downarrow \) 3384 |
\(\displaystyle \frac {4 \sqrt {2} g^3 \left (a^2-b^2\right ) \sqrt {\sin (e+f x)} \int \frac {g \cos (e+f x)}{(\sin (e+f x)+1) \sqrt {1-\frac {\cos ^2(e+f x)}{(\sin (e+f x)+1)^2}} \left ((a+b) g^2+\frac {(a-b) \cos ^2(e+f x) g^2}{(\sin (e+f x)+1)^2}\right )}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {\sin (e+f x)+1}}}{b^2 f \sqrt {d \sin (e+f x)}}+\frac {g^2 \left (-\frac {2 a d g \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}+1\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}-\frac {\frac {\log \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\log \left (-\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}\right )}{f}-\frac {b E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d f \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}\) |
\(\Big \downarrow \) 993 |
\(\displaystyle \frac {4 \sqrt {2} g^3 \left (a^2-b^2\right ) \sqrt {\sin (e+f x)} \left (\frac {\int \frac {1}{\sqrt {1-\frac {\cos ^2(e+f x)}{(\sin (e+f x)+1)^2}} \left (\sqrt {a+b} g-\frac {\sqrt {b-a} g \cos (e+f x)}{\sin (e+f x)+1}\right )}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {\sin (e+f x)+1}}}{2 \sqrt {b-a}}-\frac {\int \frac {1}{\sqrt {1-\frac {\cos ^2(e+f x)}{(\sin (e+f x)+1)^2}} \left (\sqrt {a+b} g+\frac {\sqrt {b-a} \cos (e+f x) g}{\sin (e+f x)+1}\right )}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {\sin (e+f x)+1}}}{2 \sqrt {b-a}}\right )}{b^2 f \sqrt {d \sin (e+f x)}}+\frac {g^2 \left (-\frac {2 a d g \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}+1\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}-\frac {\frac {\log \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\log \left (-\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}\right )}{f}-\frac {b E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d f \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}\) |
\(\Big \downarrow \) 1542 |
\(\displaystyle \frac {4 \sqrt {2} g^3 \left (a^2-b^2\right ) \sqrt {\sin (e+f x)} \left (\frac {\operatorname {EllipticPi}\left (\frac {\sqrt {b-a}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {\sin (e+f x)+1}}\right ),-1\right )}{2 \sqrt {g} \sqrt {b-a} \sqrt {a+b}}-\frac {\operatorname {EllipticPi}\left (-\frac {\sqrt {b-a}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {\sin (e+f x)+1}}\right ),-1\right )}{2 \sqrt {g} \sqrt {b-a} \sqrt {a+b}}\right )}{b^2 f \sqrt {d \sin (e+f x)}}+\frac {g^2 \left (-\frac {2 a d g \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}+1\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {d} \sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {d \sin (e+f x)}}\right )}{\sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}-\frac {\frac {\log \left (\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}-\frac {\log \left (-\frac {\sqrt {2} \sqrt {d} \sqrt {g} \sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)}}+g \cot (e+f x)+g\right )}{2 \sqrt {2} \sqrt {d} \sqrt {g}}}{2 d}\right )}{f}-\frac {b E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d f \sqrt {\sin (2 e+2 f x)}}\right )}{b^2}\) |
(4*Sqrt[2]*(a^2 - b^2)*g^3*(-1/2*EllipticPi[-(Sqrt[-a + b]/Sqrt[a + b]), A rcSin[Sqrt[g*Cos[e + f*x]]/(Sqrt[g]*Sqrt[1 + Sin[e + f*x]])], -1]/(Sqrt[-a + b]*Sqrt[a + b]*Sqrt[g]) + EllipticPi[Sqrt[-a + b]/Sqrt[a + b], ArcSin[S qrt[g*Cos[e + f*x]]/(Sqrt[g]*Sqrt[1 + Sin[e + f*x]])], -1]/(2*Sqrt[-a + b] *Sqrt[a + b]*Sqrt[g]))*Sqrt[Sin[e + f*x]])/(b^2*f*Sqrt[d*Sin[e + f*x]]) + (g^2*((-2*a*d*g*((-(ArcTan[1 - (Sqrt[2]*Sqrt[d]*Sqrt[g*Cos[e + f*x]])/(Sqr t[g]*Sqrt[d*Sin[e + f*x]])]/(Sqrt[2]*Sqrt[d]*Sqrt[g])) + ArcTan[1 + (Sqrt[ 2]*Sqrt[d]*Sqrt[g*Cos[e + f*x]])/(Sqrt[g]*Sqrt[d*Sin[e + f*x]])]/(Sqrt[2]* Sqrt[d]*Sqrt[g]))/(2*d) - (-1/2*Log[g + g*Cot[e + f*x] - (Sqrt[2]*Sqrt[d]* Sqrt[g]*Sqrt[g*Cos[e + f*x]])/Sqrt[d*Sin[e + f*x]]]/(Sqrt[2]*Sqrt[d]*Sqrt[ g]) + Log[g + g*Cot[e + f*x] + (Sqrt[2]*Sqrt[d]*Sqrt[g]*Sqrt[g*Cos[e + f*x ]])/Sqrt[d*Sin[e + f*x]]]/(2*Sqrt[2]*Sqrt[d]*Sqrt[g]))/(2*d)))/f - (b*Sqrt [g*Cos[e + f*x]]*EllipticE[e - Pi/4 + f*x, 2]*Sqrt[d*Sin[e + f*x]])/(d*f*S qrt[Sin[2*e + 2*f*x]])))/b^2
3.15.24.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*s) Int[(r + s*x^2)/(a + b*x^ 4), x], x] - Simp[1/(2*s) Int[(r - s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{ a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ, b]]))
Int[(x_)^2/(((a_) + (b_.)*(x_)^4)*Sqrt[(c_) + (d_.)*(x_)^4]), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2]], s = Denominator[Rt[-a/b, 2]]}, Simp[s/(2* b) Int[1/((r + s*x^2)*Sqrt[c + d*x^4]), x], x] - Simp[s/(2*b) Int[1/((r - s*x^2)*Sqrt[c + d*x^4]), x], x]] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0]
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S implify[a*(c/b^2)]}, Simp[-2/b Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b )], x] /; RationalQ[q] && (EqQ[q^2, 1] || !RationalQ[b^2 - 4*a*c])] /; Fre eQ[{a, b, c}, x]
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 2*(d/e), 2]}, Simp[e/(2*c) Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ e/(2*c) Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ -2*(d/e), 2]}, Simp[e/(2*c*q) Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Simp[e/(2*c*q) Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
Int[1/(((d_) + (e_.)*(x_)^2)*Sqrt[(a_) + (c_.)*(x_)^4]), x_Symbol] :> With[ {q = Rt[-c/a, 4]}, Simp[(1/(d*Sqrt[a]*q))*EllipticPi[-e/(d*q^2), ArcSin[q*x ], -1], x]] /; FreeQ[{a, c, d, e}, x] && NegQ[c/a] && GtQ[a, 0]
Int[Sqrt[cos[(e_.) + (f_.)*(x_)]*(b_.)]*Sqrt[(a_.)*sin[(e_.) + (f_.)*(x_)]] , x_Symbol] :> Simp[Sqrt[a*Sin[e + f*x]]*(Sqrt[b*Cos[e + f*x]]/Sqrt[Sin[2*e + 2*f*x]]) Int[Sqrt[Sin[2*e + 2*f*x]], x], x] /; FreeQ[{a, b, e, f}, x]
Int[(cos[(e_.) + (f_.)*(x_)]*(a_.))^(m_)*((b_.)*sin[(e_.) + (f_.)*(x_)])^(n _), x_Symbol] :> With[{k = Denominator[m]}, Simp[(-k)*a*(b/f) Subst[Int[x ^(k*(m + 1) - 1)/(a^2 + b^2*x^(2*k)), x], x, (a*Cos[e + f*x])^(1/k)/(b*Sin[ e + f*x])^(1/k)], x]] /; FreeQ[{a, b, e, f}, x] && EqQ[m + n, 0] && GtQ[m, 0] && LtQ[m, 1]
Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticE[(1/2)* (c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n _.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[a Int[(g*Co s[e + f*x])^p*(d*Sin[e + f*x])^n, x], x] + Simp[b/d Int[(g*Cos[e + f*x])^ p*(d*Sin[e + f*x])^(n + 1), x], x] /; FreeQ[{a, b, d, e, f, g, n, p}, x]
Int[((cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((d_.)*sin[(e_.) + (f_.)*(x_)])^( n_))/((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[g^2/b^2 In t[(g*Cos[e + f*x])^(p - 2)*(d*Sin[e + f*x])^n*(a - b*Sin[e + f*x]), x], x] - Simp[g^2*((a^2 - b^2)/b^2) Int[(g*Cos[e + f*x])^(p - 2)*((d*Sin[e + f*x ])^n/(a + b*Sin[e + f*x])), x], x] /; FreeQ[{a, b, d, e, f, g}, x] && NeQ[a ^2 - b^2, 0] && IntegersQ[2*n, 2*p] && GtQ[p, 1]
Int[Sqrt[cos[(e_.) + (f_.)*(x_)]*(g_.)]/(Sqrt[sin[(e_.) + (f_.)*(x_)]]*((a_ ) + (b_.)*sin[(e_.) + (f_.)*(x_)])), x_Symbol] :> Simp[-4*Sqrt[2]*(g/f) S ubst[Int[x^2/(((a + b)*g^2 + (a - b)*x^4)*Sqrt[1 - x^4/g^2]), x], x, Sqrt[g *Cos[e + f*x]]/Sqrt[1 + Sin[e + f*x]]], x] /; FreeQ[{a, b, e, f, g}, x] && NeQ[a^2 - b^2, 0]
Int[Sqrt[cos[(e_.) + (f_.)*(x_)]*(g_.)]/(Sqrt[(d_)*sin[(e_.) + (f_.)*(x_)]] *((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])), x_Symbol] :> Simp[Sqrt[Sin[e + f* x]]/Sqrt[d*Sin[e + f*x]] Int[Sqrt[g*Cos[e + f*x]]/(Sqrt[Sin[e + f*x]]*(a + b*Sin[e + f*x])), x], x] /; FreeQ[{a, b, d, e, f, g}, x] && NeQ[a^2 - b^2 , 0]
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 4108 vs. \(2 (474 ) = 948\).
Time = 3.04 (sec) , antiderivative size = 4109, normalized size of antiderivative = 7.18
-1/f*g^2*(a-b)*(g*cos(f*x+e))^(1/2)/(d*sin(f*x+e))^(1/2)*(2*sec(f*x+e)*(-a ^2+b^2)^(1/2)*(-cot(f*x+e)+csc(f*x+e)+1)^(1/2)*(-csc(f*x+e)+cot(f*x+e)+1)^ (1/2)*(-csc(f*x+e)+cot(f*x+e))^(1/2)*EllipticE((-cot(f*x+e)+csc(f*x+e)+1)^ (1/2),1/2*2^(1/2))*a*b-I*sec(f*x+e)*(-a^2+b^2)^(1/2)*(-cot(f*x+e)+csc(f*x+ e)+1)^(1/2)*(-csc(f*x+e)+cot(f*x+e)+1)^(1/2)*(-csc(f*x+e)+cot(f*x+e))^(1/2 )*EllipticPi((-cot(f*x+e)+csc(f*x+e)+1)^(1/2),1/2+1/2*I,1/2*2^(1/2))*a^2+I *sec(f*x+e)*(-a^2+b^2)^(1/2)*EllipticPi((-cot(f*x+e)+csc(f*x+e)+1)^(1/2),1 /2-1/2*I,1/2*2^(1/2))*(-cot(f*x+e)+csc(f*x+e)+1)^(1/2)*(-csc(f*x+e)+cot(f* x+e)+1)^(1/2)*(-csc(f*x+e)+cot(f*x+e))^(1/2)*a^2-sec(f*x+e)*(-a^2+b^2)^(1/ 2)*(-cot(f*x+e)+csc(f*x+e)+1)^(1/2)*(-csc(f*x+e)+cot(f*x+e)+1)^(1/2)*(-csc (f*x+e)+cot(f*x+e))^(1/2)*EllipticF((-cot(f*x+e)+csc(f*x+e)+1)^(1/2),1/2*2 ^(1/2))*a*b+EllipticPi((-cot(f*x+e)+csc(f*x+e)+1)^(1/2),-a/(b+(-a^2+b^2)^( 1/2)-a),1/2*2^(1/2))*a*b^2*(-cot(f*x+e)+csc(f*x+e)+1)^(1/2)*(-csc(f*x+e)+c ot(f*x+e)+1)^(1/2)*(-csc(f*x+e)+cot(f*x+e))^(1/2)-EllipticPi((-cot(f*x+e)+ csc(f*x+e)+1)^(1/2),a/(-b+(-a^2+b^2)^(1/2)+a),1/2*2^(1/2))*a*b^2*(-cot(f*x +e)+csc(f*x+e)+1)^(1/2)*(-csc(f*x+e)+cot(f*x+e)+1)^(1/2)*(-csc(f*x+e)+cot( f*x+e))^(1/2)-(-a^2+b^2)^(1/2)*2^(1/2)*a*b-2*(-a^2+b^2)^(1/2)*(-cot(f*x+e) +csc(f*x+e)+1)^(1/2)*(-csc(f*x+e)+cot(f*x+e)+1)^(1/2)*(-csc(f*x+e)+cot(f*x +e))^(1/2)*EllipticF((-cot(f*x+e)+csc(f*x+e)+1)^(1/2),1/2*2^(1/2))*b^2-sec (f*x+e)*(-cot(f*x+e)+csc(f*x+e)+1)^(1/2)*(-csc(f*x+e)+cot(f*x+e)+1)^(1/...
Timed out. \[ \int \frac {(g \cos (e+f x))^{5/2}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\text {Timed out} \]
Timed out. \[ \int \frac {(g \cos (e+f x))^{5/2}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\text {Timed out} \]
\[ \int \frac {(g \cos (e+f x))^{5/2}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\int { \frac {\left (g \cos \left (f x + e\right )\right )^{\frac {5}{2}}}{{\left (b \sin \left (f x + e\right ) + a\right )} \sqrt {d \sin \left (f x + e\right )}} \,d x } \]
\[ \int \frac {(g \cos (e+f x))^{5/2}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\int { \frac {\left (g \cos \left (f x + e\right )\right )^{\frac {5}{2}}}{{\left (b \sin \left (f x + e\right ) + a\right )} \sqrt {d \sin \left (f x + e\right )}} \,d x } \]
Timed out. \[ \int \frac {(g \cos (e+f x))^{5/2}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))} \, dx=\int \frac {{\left (g\,\cos \left (e+f\,x\right )\right )}^{5/2}}{\sqrt {d\,\sin \left (e+f\,x\right )}\,\left (a+b\,\sin \left (e+f\,x\right )\right )} \,d x \]